# Play these fun Math Games Now.

WELCOME TO PUZZLES-ONLINE-NICHE

You can play these fun math games below. We also include for each section, helps , hints

and strategies.

• Verbal Arithmetic

RULES:

You are presented with a phrase which is actually in the form of a mathematical problem, but

the numbers have been hidden by letters (or sometimes symbols).

• The goal is to identify the value of each letter.
• Each letter represents one and only one number.
• You can use the numbers 0-9.
• ALL standard mathematical rules apply
• No leading digit can contain zero.

NOTE:. Verbal math games can be useful as a motivation and source of exercises in the

teaching of algebra, because they use the property of number substitution, with representation by letters.

Helps , hints and strategies.

Solving math games puzzle by hand usually involves a mix of deductions and exhaustive tests of possibilities.

For instance, the following sequence of deductions solves Dudeney's SEND + MORE = MONEY puzzle

below(columns are numbered from right to left):

 From column 5, M = 1 since it is the only carry-over possible from the sum of two single digit numbers in column 4.To produce a carry from column 4 to column 5, S + M is at least 9, so S is 8 or 9, so S + M is 9 or 10, and so O is 0 or 1. But M = 1, so O = 0.If there were a carry from column 3 to column 4 then E = 9 and so N = 0. But O = 0, so there is no carry, and S = 9.If there were no carry from column 2 to column 3 then E = N, which is impossible. Therefore there is a carry and N = E + 1.If there were no carry from column 1 to column 2, then ( N + R ) mod 10 = E, and N = E + 1, so E + 1 + R = E mod 10, so R = 9. But S = 9, so there must be a carry from column 1 to column 2 and R = 8.To produce a carry from column 1 to column 2, we must have D + E = 10 + Y. As Y cannot be 0 or 1, D + E is at least 12. As D is at most 7, then E is at least 5. Also, N is at most 7, and N = E + 1. So E is 5 or 6.If E were 6 then to make D + E at least 12, D would have to be 7. But N = E + 1, so N would also be 7, which is impossible. Therefore E = 5 and N = 6.To make D + E at least 12 we must have D = 7, and so Y = 2.

Try these verbal math games:

 Verbal Math -1M A T H- I S= F U NVerbal Math -2L E S S- I S= M O R EVerbal Math -3P L A Y+ T H E= G A M EVerbal Math -4I C E + C U B E= C O O LVerbal Math -5S U N+ T A N= B U R N Verbal Math -6P A S S+ T H E= B U C KVerbal Math -7B E A T+ T H E= D R U MVerbal Math -8R I D E+T H E= W A V EVerbal Math- 9F E A R+ N O= E V I LVerbal Math-10W A L K- T H E= D O G

## Solutions

KEY CODES:

Verbal Math 1-SOLUTION

### Verbal Math 1(show / hide)

M = 1, A = 0, T = 2, H = 3, I = 7, S = 8, F = 9, U = 4, N = 5.
Verbal math 3-SOLUTION

### Verbal math 3(show / hide)

P=2, L =8, A =4, Y =0, T=6, H =1, E =9, G =3, M =5
Verbal math 5-SOLUTION

### Verbal math 5(show / hide)

: S=8, U =3, N =0, T =5, A =4, B =1, R =7
Verbal math 7-SOLUTION

### Verbal math 7(show / hide)

0= M,1= R,3= U,4= T,5= H,6= E,7= A,8= B,9= D.
Verbal math 9-SOLUTION

### Verbal math 9(show / hide)

0= V,1= I,2= O,3= R, 4= N,5= L,7= A,8= F,9= E.
Verbal math 2-SOLUTION

### Verbal math 2(show / hide)

L = 2, E =0, S =5, I =7, M =1, O =9 R= 8
Verbal math 4-SOLUTION

### Verbal math 4(show / hide)

I =3, C=6, E =7, U =1, B =8, O =5, L =4
Verbal math 6-SOLUTION

### Verbal math 6(show / hide)

0= C,1= S,2= U,3= P 4= B,5= A,6= T,7= E,8= K,9= H.
Verbal math 8-SOLUTION

### Verbal math 8(show / hide)

0= E,2= A,3= I,4= V,5= D,6= R,7= W,8= T,9= H.
Verbal math 10-SOLUTION

### Verbal math 10(show / hide)

0= A,1= W,2= G,3= D, 4= O,5= H,6= E,7= T,8= K,9= L.