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You can play these fun math games below. We also include for each section, helps , hints

and strategies.

  • Verbal Arithmetic

RULES:

You are presented with a phrase which is actually in the form of a mathematical problem, but

the numbers have been hidden by letters (or sometimes symbols).

  • The goal is to identify the value of each letter.
  • Each letter represents one and only one number.
  • You can use the numbers 0-9.
  • ALL standard mathematical rules apply
  • No leading digit can contain zero.

NOTE:. Verbal math games can be useful as a motivation and source of exercises in the

teaching of algebra, because they use the property of number substitution, with representation by letters.

Helps , hints and strategies.

Solving math games puzzle by hand usually involves a mix of deductions and exhaustive tests of possibilities.

For instance, the following sequence of deductions solves Dudeney's SEND + MORE = MONEY puzzle

below(columns are numbered from right to left):
  1. From column 5, M = 1 since it is the only carry-over possible from the sum of two single digit numbers in column 4.
  2. To produce a carry from column 4 to column 5, S + M is at least 9, so S is 8 or 9, so S + M is 9 or 10, and so O is 0 or 1. But M = 1, so O = 0.
  3. If there were a carry from column 3 to column 4 then E = 9 and so N = 0. But O = 0, so there is no carry, and S = 9.
  4. If there were no carry from column 2 to column 3 then E = N, which is impossible. Therefore there is a carry and N = E + 1.
  5. If there were no carry from column 1 to column 2, then ( N + R ) mod 10 = E, and N = E + 1, so E + 1 + R = E mod 10, so R = 9. But S = 9, so there must be a carry from column 1 to column 2 and R = 8.
  6. To produce a carry from column 1 to column 2, we must have D + E = 10 + Y. As Y cannot be 0 or 1, D + E is at least 12. As D is at most 7, then E is at least 5. Also, N is at most 7, and N = E + 1. So E is 5 or 6.
  7. If E were 6 then to make D + E at least 12, D would have to be 7. But N = E + 1, so N would also be 7, which is impossible. Therefore E = 5 and N = 6.
  8. To make D + E at least 12 we must have D = 7, and so Y = 2.

Try these verbal math games:

Verbal Math -1

M A T H

    - I S

= F U N


Verbal Math -2

L E S S

    - I S

= M O R E


Verbal Math -3

P L A Y

+ T H E

= G A M E

Verbal Math -4

I C E

+ C U B E

= C O O L

Verbal Math -5

    S U N

    + T A N

    = B U R N

Verbal Math -6

P A S S

+ T H E

= B U C K

Verbal Math -7

B E A T

+ T H E

= D R U M

Verbal Math -8

R I D E

+T H E

= W A V E

Verbal Math- 9

F E A R

+ N O

= E V I L

Verbal Math-10

W A L K

- T H E

= D O G


Solutions :FLASHING HEADER

Solutions

KEY CODES:

Verbal Math 1-SOLUTION

Verbal Math 1
(show / hide)

M = 1, A = 0, T = 2, H = 3, I = 7, S = 8, F = 9, U = 4, N = 5.
Verbal math 3-SOLUTION

Verbal math 3
(show / hide)

P=2, L =8, A =4, Y =0, T=6, H =1, E =9, G =3, M =5
Verbal math 5-SOLUTION

Verbal math 5
(show / hide)

: S=8, U =3, N =0, T =5, A =4, B =1, R =7
Verbal math 7-SOLUTION

Verbal math 7
(show / hide)

0= M,1= R,3= U,4= T,5= H,6= E,7= A,8= B,9= D.
Verbal math 9-SOLUTION

Verbal math 9
(show / hide)

0= V,1= I,2= O,3= R, 4= N,5= L,7= A,8= F,9= E.
Verbal math 2-SOLUTION

Verbal math 2
(show / hide)

L = 2, E =0, S =5, I =7, M =1, O =9 R= 8
Verbal math 4-SOLUTION

Verbal math 4
(show / hide)

I =3, C=6, E =7, U =1, B =8, O =5, L =4
Verbal math 6-SOLUTION

Verbal math 6
(show / hide)

0= C,1= S,2= U,3= P 4= B,5= A,6= T,7= E,8= K,9= H.
Verbal math 8-SOLUTION

Verbal math 8
(show / hide)

0= E,2= A,3= I,4= V,5= D,6= R,7= W,8= T,9= H.
Verbal math 10-SOLUTION

Verbal math 10
(show / hide)

0= A,1= W,2= G,3= D, 4= O,5= H,6= E,7= T,8= K,9= L.
Solutions :FLASHING HEADER

Solutions

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